#13185DPA Numbers I

In number theory, a positive integer belongs to one and only one of the following categories: Deficient, Perfect or Abundant (DPA). To decide the category of a positive integer n, first you have to calculate the sum of all its proper positive divisors. If the result is less than n then n is a deficient number, if the result is equal to n then n is a perfect number and if the result is greater than n then n is an abundant number. Remember that the proper divisors of n don’t include n itself. For example, the proper divisors of the number 8 are 1, 2 and 4 which sum 7. Since 7 < 8 therefore 8 is a deficient number. The proper divisors of the number 6 are 1, 2 and 3 which sum 6. Since 6 = 6 therefore 6 is a perfect number. The proper divisors of the number 18 are 1, 2, 3, 6 and 9 which sum 21. Since 21 > 18 therefore 18 is an abundant number.

The task is to choose the category of a positive integer n as a deficient, perfect or abundant number.

Input

Input begins with an integer t (1 ≤ t ≤ 500), the number of test cases, followed by t lines, each line containing an integer n (2 ≤ n ≤ 10^3).

Output

For each test case, you should print a single line containing the word ‘deficient’, ‘perfect’ or ‘abundant’ that representing the category of the number n.

10
5
6
16
18
21
28
29
30
40
43

deficient
perfect
deficient
abundant
deficient
perfect
deficient
abundant
abundant
deficient