Our Black Box represents a primitive database. It can save an integer array and has a special i variable. At the initial moment Black Box is empty and i equals 0. This Black Box processes a sequence of commands (transactions). There are two types of transactions:
Keep in mind that i-minimum is a number located at i-th place after Black Box elements sorting by non-descending. Example Let us examine a possible sequence of 11 transactions: N Transaction i Black Box contents after transaction Answer (elements are arranged by non-descending) 1 ADD(3) 0 3 2 GET 1 3 3 3 ADD(1) 1 1, 3 4 GET 2 1, 3 3 5 ADD(-4) 2 -4, 1, 3 6 ADD(2) 2 -4, 1, 2, 3 7 ADD(8) 2 -4, 1, 2, 3, 8 8 ADD(-1000) 2 -1000, -4, 1, 2, 3, 8 9 GET 3 -1000, -4, 1, 2, 3, 8 1 10 GET 4 -1000, -4, 1, 2, 3, 8 2 11 ADD(2) 4 -1000, -4, 1, 2, 2, 3, 8 It is required to work out an efficient algorithm which treats a given sequence of transactions. The maximum number of ADD and GET transactions: 30000 of each type. Let us describe the sequence of transactions by two integer arrays:
The Black Box algorithm supposes that natural number sequence u(1), u(2), . . . , u(N ) is sorted in non-descending order, N ≤ M and for each p (1 ≤ p ≤ N ) an inequality p ≤ u(p) ≤ M is valid. It follows from the fact that for the p-element of our u sequence we perform a GET transaction giving p-minimum number from our A(1), A(2), . . . , A(u(p)) sequence.
The first line of the input is an integer K, then a blank line followed by K datasets. There is a blank line between datasets. Input for each dataset contains (in given order): M, N, A(1), A(2), . . . , A(M ), u(1), u(2), . . . , u(N ). All numbers are divided by spaces and (or) carriage return characters.
For each dataset, write to the output Black Box answers sequence for a given sequence of transactions. Write only a number per line in the output. Print a blank line between datasets.
範例輸入 1
1 7 4 3 1 -4 2 8 -1000 2 1 2 6 6
範例輸出 1
3 3 1 2
Pro 專屬功能: 查看這題在歷屆 CPE 出現過幾次 — 升級以解鎖.