| N | Transaction | i | Black Box contents after transaction | Answer |
|---|
| 1 | ADD(3) | 0 | 3 | |
| 2 | GET | 1 | 3 | 3 |
| 3 | ADD(1) | 1 | 1, 3 | |
| 4 | GET | 2 | 1, 3 | 3 |
| 5 | ADD(-4) | 2 | -4, 1, 3 | |
| 6 | ADD(2) | 2 | -4, 1, 2, 3 | |
| 7 | ADD(8) | 2 | -4, 1, 2, 3, 8 | |
| 8 | ADD(-1000) | 2 | -1000, -4, 1, 2, 3, 8 | |
| 9 | GET | 3 | -1000, -4, 1, 2, 3, 8 | 1 |
| 10 | GET | 4 | -1000, -4, 1, 2, 3, 8 | 2 |
| 11 | ADD(2) | 4 | -1000, -4, 1, 2, 2, 3, 8 |
It is required to work out an efficient algorithm which treats a given sequence of transactions. The maximum number of ADD and GET transactions: 30000 of each type.
Let us describe the sequence of transactions by two integer arrays:
The Black Box algorithm supposes that natural number sequence u(1), u(2), . . . , u(N ) is sorted in non-descending order, N ≤ M and for each p (1 ≤ p ≤ N ) an inequality p ≤ u(p) ≤ M is valid. It follows from the fact that for the p-element of our u sequence we perform a GET transaction giving p-minimum number from our A(1), A(2), . . . , A(u(p)) sequence.
The first line of the input is an integer K, then a blank line followed by K datasets. There is a blank line between datasets.
Input for each dataset contains (in given order): M, N, A(1), A(2), . . . , A(M ), u(1), u(2), . . . , u(N ). All numbers are divided by spaces and (or) carriage return characters.
For each dataset, write to the output Black Box answers sequence for a given sequence of transactions. Write only a number per line in the output.
Print a blank line between datasets.